Page 412 - Computer Science V2.0 Class 11

Approach:
a. First create a tuple of categories:
clothCategory = ('wedding', 'casual', 'party', 'sports')
b. Intialise count of each type of clothing to 0:
countW,countC, countP, countS = 0, 0, 0, 0
c. For each input (type of clothing):
i. If in the clothCategory, increment the appropriate count
ii. Otherwise print an error message
Ans. '''
Objective: To count clothing for each category
Input: clothing ids, clothing names, and clothing categories
Output: category-wise count
'''
clothCategory = ('wedding collection', 'casual wear', 'party wear', 'sports wear')
countW, countC, countP, countS = 0, 0, 0, 0
continueOrNot = 'y'
clothingList = []

while continueOrNot =='y':
clothingId = int(input("Enter the clothing id : "))
clothingName = input("Enter name of the clothing : ")
inputCategory = input("Enter category of clothing : ")

if inputCategory not in clothCategory:
print(" Sorry...We do not deal with ", inputCategory)
continue

clothRecord = [clothingId,clothingName,inputCategory]

clothingList.append(clothRecord)
continueOrNot = input(" Do you wish to continue (y/n): ")
for record in clothingList:
if record[2] == 'wedding collection':
countW += 1
elif record[2] == 'casual wear':
countC += 1
elif record[2] == 'party wear':
countP += 1
elif record[2] == 'sports wear':
countS += 1
print(clothingList)
print("Category Wise data is : ")
print('Wedding Collection: ', countW)
print('Casual Wear: ', countC)
print('Party Wear: ', countP)
print('Sports Wear: ',countS)

398 Touchpad Computer Science (Ver. 2.0)-XI