Page 431 - Computer Science V2.0 Class 11

Sample output:
Want to add more word and synonyms?(Y/y):n
beautiful ('alluring', 'delightful', 'charming', 'pleasing', 'attractive')
lovely ('cute', 'dazzling')
pretty ('nice-looking', 'beautiful')
Do you want synonyms of a word,Reply Y/y of N/n?y
>>> Enter a word:furious
No synonyms found
Want to add furious to thesaurus?,Reply Y/y of N/n?
y
>>> Enter synonyms as a tuple('angry', 'wild', 'stormy')
Do you want synonyms of a word,Reply Y/y of N/n?y
>>> Enter a word:irate
No synonyms found
Want to add irate to thesaurus?,Reply Y/y of N/n?
y
>>> Enter synonyms as a tuple('boiling', 'furious', 'heated')
Do you want synonyms of a word,Reply Y/y of N/n?y
>>> Enter a word:furious
synonyms of furious : {'angry', 'furious', 'irate', 'boiling', 'wild', 'stormy', 'heated'}
Do you want synonyms of a word,Reply Y/y of N/n?y
>>> Enter a word:heated
synonyms of heated : {'furious', 'irate', 'boiling', 'heated'}
Do you want synonyms of a word,Reply Y/y of N/n?

Solved Programming Questions

1. Write a function wordCountDict(lst)to find the number of occurrences of each word in a list of words in the
form of a dictionary. Apply the function wordCountDict(lst)to a list entered by the user.
01 def wordCountDict(lst):
02 '''
03 Objective: To find word frequency of words in a list.
04 Input Parameter: lst - list containing words
05 Return Value: Dictionary of words and their frequencies
06 '''
07 '''
08 Approach:
09 For each word w in list
10 if w is in dictionary, increment its count
11 else add w to the dictionary with 1 as its count
12 '''
13 wordCount = dict()
14 for w in lst:
15 if w in wordCount:
16 wordCount[w] += 1
17 else:
18 wordCount[w] = 1
19 return wordCount
20
21 #Objective: To find frequency of words given in a list.
22 lst = eval(input('Enter the list: '))
23 print('Dictionary of word count:: ', wordCountDict(lst))
Sample Output:
>>> Enter the list: ["apple","banana","apple","apple","banana"]
Dictionary of word count:: {'apple': 3, 'banana': 2}

Dictionaries 417