Page 51 - Computer Science V2.0 Class 11
P. 51

Step 2: Binary to octal
                         added one 0
                   0    1    1  1 0    0 1    1 1

                      3         4        7
                 Octal equivalent of (11100111)  is (347) 8
                                            2
                 Alternatively,  you  may  first  convert  the  hexadecimal  number  to  its  decimal  equivalent  and  then  find  the  octal
                 representation of the decimal number.




                         Find octal representation of (14) , (23) and (81) .
                                                                 16
                                                         16
                                                   16

                 Do the following conversions:
                   a.  (436)  to binary
                           10
                   b.  (11011)  to decimal
                             2
                   c.  (195)  to octal
                           10
                   d.  (706) to decimal
                           8
                   e.  (942)  to hexadecimal
                           10
                   f.  (A19)  to decimal
                           16
                   g.  (1010110)   to octal
                                2
                   h.  (732)  to binary
                           8
                   i.  (101011100)  to hexadecimal
                                 2
                   j.  (F31)  to binary
                           16
                   k.  (474)  to hexadecimal
                           8
                   l.  (C8E)  to octal
                           16
                 Ans.  a. (436)  to binary
                             10
                        2   436         Remainder
                        2   218            0

                        2   109            0
                        2    54            1
                        2    27            0
                        2    13            1
                        2     6            1

                        2     3            0
                        2     1            1
                        2      0           1

                      (436)  = (110110100) 2
                           10
                 b.  (11011)  to decimal
                          2
                   Face Value       1     1    0    1     1
                   Place value      2 4   2 3  2 2  2 1   2 0

                                               1
                   = 1 × 2  + 1 × 2  + 0 × 2  + 1 × 2  + 1 × 2 0
                         4
                                       2
                                3
                                                                                 Number Systems and Encoding Schemes  37
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