Page 64 - Computer Science V2.0 Class 11
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Find octal representation of (9.7) , (5A.AF) , and (C4.98) .
                                                 16
                                                         16
                                                                     16
              Conversion of Octal Numbers to Hexadecimal
              To convert an octal number to a hexadecimal number, first convert it to a binary number and then convert the binary
              number to hexadecimal number.
              Example 48: Convert (75.36) to a hexadecimal number
                                        8
              (75.36) 8
                        7         5   .    3        6
                        ↓        ↓         ↓        ↓
                       111      101       011      110
              Binary equivalent of (75.36)  is (111101.011110)
                                       8                 2
                      two 0s added                   two 0s added

                        0 0 1 1 1 1 0 1  .  0 1 1 1 1 0 0 0

                          3       D     .     7      8

              Hexadecimal equivalent of (111101.011110)  is (3D.78) 16
                                                     2


                      1. Write binary and octal equivalents for the following hexadecimal digits:
                        F, A, 5, C
                      2. Find hexadecimal representation of (10.5) , (32.6)  and (40.3) .
                                                                          8
                                                                 8
                                                          8

              Do the following conversions:
              a.  (10011.01)  to decimal
                            2
              b.  (C25.D2)  to decimal
                          16
              c.  (157.25)  to decimal
                         8
              d.  (0.341)  to hexadecimal
                        10
              Ans:
              a.  (10011.01)  to decimal number.
                            2
                  Face Value         1      0     0     1    1  .    0      1
                                                              0
                  Place value        2 4   2 3    2 2   2 1  2  .   2 –1   2 –2
                        4
                               3
                                      2
                                                           –1
                                                    0
                                             1
                  = 1 × 2  + 0 × 2  + 0 × 2 + 1 × 2 + 1 × 2 + 0 × 2 + 1 × 2 –2
                  = 16 + 0 + 0 + 2 + 1 + 0 +   1
                                        4
                  = 19 + 0.25
                  = 19.25
                  = (10011.01)  = (19.25) 10
                             2
              b.  (C25.D2)  to decimal number.
                          16
                  Face Value         C      2     5  .   D     2
                                                         –1
                                                  0
                                             1
                                      2
                  Place value       16     16   16   .  16   16 –2
                  = C × 16  + 2 × 16  + 5 × 16 + D × 16 + 2 × 16 –2
                                 1
                                          0
                                                  –1
                         2
                  = 12 × 256 + 2 × 16 + 5 × 1 +  13  +   2
                                           16   256
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