Page 76 - Computer Science V2.0 Class 11

iv.
8 889
8 111 1

8 13 7
8 1 5

0 1
= (1571) 8
v.
16 789
16 49 5

16 3 1
0 3

(315) 16
vi.
16 108
16 6 C
0 6

= (6C) 16
5. Express the following octal numbers into their equivalent decimal numbers.
i. 145
ii. 6760
iii. 455
iv. 10.75
Ans. i. 145
Digits 1 4 5

Position 2 1 0
Weight 8 2 8 1 8 0
Therefore,
2
Decimal number = 1×8 +4×8 + 5×8 0
1
= 1×64 + 4×8 + 5× 1
= 64 + 32 + 5
= (101) 10
ii.

Digits 6 7 6 0
Position 3 2 1 0

Weight 8 3 8 2 8 1 8 0
Therefore,
Decimal number = 6×8 +7×8 +6×8 + 0×8 0
1
2
3
= 6×512 + 7×64 +6×8 + 0× 1
= 3072 + 448 + 48+0
= (3568) 10

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