Page 77 - Computer Science V2.0 Class 11

iii.

Digits 4 5 5
Position 2 1 0
Weight 8 2 8 1 8 0
Therefore,
2
Decimal number = 4×8 +5×8 + 5×8 0
1
= 4×64 + 5×8 + 5× 1
= 256 + 40 + 5
= (301) 10
iv.

Digits 1 0 7 5
Position 1 0 -1 -2

Weight 8 1 8 0 8 -1 8 -2
Therefore,
0
-1
1
Decimal number = 1×8 +0×8 +7×8 +5×8 -2
= 1×8+0×1+7×0.125+5×0.015625
= 8+0+0.875+0.078125
= (8.953125) 10
6. Express the following decimal numbers into hexadecimal numbers.

i. 548
ii. 4052
iii. 58
iv. 100.25
Ans. i.

16 548
16 34 4
16 2 2

0 2
= (224) 16
ii.
16 4052
16 243 4

16 15 D
0 F

= (FD4) 16
iii.

16 58
16 3 A
0 3

= (3A) 16

Number Systems and Encoding Schemes 63