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+ and ● are also called disjunction and conjunction, respectively.


                 1.  Closure Property
                    (1)  a + b ∈ S, ∀ a, b ∈ S

                    (2)  a ● b ∈ S, ∀ a, b ∈ S
                 2.  Commutative Property
                    (1)  a + b = b + a, ∀ a, b ∈ S
                    (2)  a ● b = b ● a, ∀ a, b ∈ S

                 3.  Distributive Property
                    (1)  a + (b ● c) = (a + b) ● (a + c), ∀ a, b, c ∈ S
                    (2)  a ● (b + c) = a ● b + a ● c, ∀ a, b, c ∈ S
                 4.  Identity Property
                    There exist two elements in S, denoted by 0 and 1, called identity of + and ● respectively, satisfying

                    (1)  a + 0 = a, ∀ a ∈ S
                    (2)  a ● 1 = a, ∀ a ∈ S
                 5.  Complementarity Property
                    For each a ∈ S, there exists an element in S, denoted by a', such that

                    (1)  a + a' = 1
                    (2)  a ● a' = 0
                    a' is called the complement of a.

                 3.3.2 Important Theorems

                 Below we give some useful properties of Boolean algebra that can be proved using the above-mentioned properties.
                 Theorem 1: Uniqueness of complements: For each element a ∈ S, its complement is unique. The complement of 0 is
                 1 and the complement of 1 is 0.
                 Theorem 2: Universal bounds: For ∀ a ∈ S,
                    (i)  a + 1 = 1
                    (ii)  a ● 0 = 0

                 We can verify Theorem 2 using Table 3.5

                                       a              a+ 1                       a              a.0

                                       0               1                         0               0
                                       1               1                         1               0
                                             a+ 1 = 1                                 a.0 = 0

                                                     Table 3.5: a + 1 = 1 and a.0 = 0
                 Theorem 3: Absorption Law: ∀ a, b ∈ S

                     (i)  a + a ● b = a
                    (ii)  a ● (a + b) = a






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